One minute
Leetcode 1689
1689. Partitioning Into Minimum Number Of Deci-Binary Numbers
The idea of this solution is that the max digit in n
will be the result. But you might be wondering why this works.
This works because the max digit can only be made by adding the max digit number of 1
’s. If you don’t understand, look at the following image: The first image is an example, and the second example is for anyone who doesn’t understand the first example.
The Code:
func minPartitions(n string) int {
max := '0'
for _, i := range n {
if i > max {
max = i
}
}
return int(max - '0')
}
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